Question

solve for g.
g - 17 ≥ 0 or $\frac{5g + 2}{2}$ ≤ 6
write your answer as a compound inequality with integers.

Explanation:

Step1: Solve the first inequality

Add 17 to both sides of $g - 17\geq0$.
$g-17 + 17\geq0 + 17$
$g\geq17$

Step2: Solve the second inequality

Multiply both sides of $\frac{5g + 2}{2}\leq6$ by 2.
$5g+2\leq12$
Then subtract 2 from both sides.
$5g+2 - 2\leq12 - 2$
$5g\leq10$
Divide both sides by 5.
$g\leq2$

Answer:

$g\leq2$ or $g\geq17$