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Question
solve for x. \\(\log_3 (4x - 19) = 4\\) \\(x = \square\\)
Step1: Convert log to exponential form
$\log_b(a)=c \implies b^c=a$, so $3^4 = 4x - 19$
Step2: Calculate $3^4$
$3^4 = 81$, so $81 = 4x - 19$
Step3: Isolate the term with $x$
Add 19 to both sides: $81 + 19 = 4x$
$100 = 4x$
Step4: Solve for $x$
Divide by 4: $x = \frac{100}{4}$
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$x = 25$