Question

solve \\((5m + 4)^2 = 0\\).\\(m = \square\\)

Explanation:

Step1: Take square root of both sides

To solve the equation \((5m + 4)^2 = 0\), we start by taking the square root of both sides. The square root of a square is the absolute value of the expression inside, but since the right - hand side is 0, we have:
\(\sqrt{(5m + 4)^2}=\sqrt{0}\)
Which simplifies to \(|5m + 4| = 0\). And since the absolute value of a number is 0 only when the number itself is 0, we get \(5m+4 = 0\).

Step2: Solve for m

Now we solve the linear equation \(5m+4 = 0\) for \(m\).
Subtract 4 from both sides of the equation:
\(5m+4 - 4=0 - 4\)
\(5m=-4\)
Then divide both sides by 5:
\(m=\frac{-4}{5}\)

Answer:

\(m =-\frac{4}{5}\)