Question

1. $-\frac{f}{5}+12 = -2$ solve check
2. $\frac{-c}{3}+8 = -7$ solve check
3. $3t - 2$
4. $16$

Explanation:

For problem 5:

Step1: Subtract 12 from both sides

$-\frac{f}{5} + 12 - 12 = -2 - 12$
$-\frac{f}{5} = -14$

Step2: Multiply by -5 on both sides

$-\frac{f}{5} \times (-5) = -14 \times (-5)$
$f = 70$

Step3: Check the solution

Substitute $f=70$ into original equation:
$-\frac{70}{5} + 12 = -14 + 12 = -2$, which matches the right-hand side.

For problem 7:

Step1: Subtract 8 from both sides

$\frac{-c}{3} + 8 - 8 = -7 - 8$
$\frac{-c}{3} = -15$

Step2: Multiply by -3 on both sides

$\frac{-c}{3} \times (-3) = -15 \times (-3)$
$c = 45$

Step3: Check the solution

Substitute $c=45$ into original equation:
$\frac{-45}{3} + 8 = -15 + 8 = -7$, which matches the right-hand side.

Answer:

Problem 5: $f=70$
Problem 7: $c=45$