Question

1. solve for ( y ) in the equation ( 4y - 2x = 8 ).

a. ( y = -\frac{1}{2}x + 2 )

b. ( y = \frac{1}{2}x + 2 )

c. ( y = 2x + 4 )

d. ( y = -2x + 4 )

Explanation:

Step1: Isolate the y-term

$4y = 2x + 8$

Step2: Solve for y by dividing by 4

$y = \frac{2x + 8}{4} = \frac{1}{2}x + 2$

Answer:

b. $y = \frac{1}{2}x + 2$