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Question
solve the equation. if necessary, round to the nearest hundredth.\\(x^3 - 6x^2 + 4x = -6\\)\\(\bigcirc\\) a) \\(-0.69, 1.75, 4.95\\)\\(\bigcirc\\) b) \\(-0.69, -1.75, 4.95\\)\\(\bigcirc\\) c) \\(-0.69, 4.95\\)\\(\bigcirc\\) d) no solution
Step1: Rearrange equation to standard form
$x^3 - 6x^2 + 4x + 6 = 0$
Step2: Use rational root theorem (no rational roots)
Test $\pm1,\pm2,\pm3,\pm6$; none satisfy the equation.
Step3: Apply numerical root-finding method
Use Newton-Raphson method or calculator to approximate roots:
- First root: $x \approx -0.69$
- Second root: $x \approx 1.75$
- Third root: $x \approx 4.95$
Step4: Verify roots in original equation
Substitute each root into $x^3 - 6x^2 + 4x$; results are $\approx -6$.
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A) -0.69, 1.75, 4.95