Question

solve the following compound inequality.
$-1 leq \frac{d + 2}{5} leq \frac{6}{5}$
$? leq d leq $

Explanation:

Step1: Multiply all parts by 5

To eliminate the denominator, we multiply each part of the compound inequality by 5. This gives us:
$$-1\times5\leq\frac{d + 2}{5}\times5\leq\frac{6}{5}\times5$$
Simplifying each part, we have:
$$-5\leq d + 2\leq6$$

Step2: Subtract 2 from all parts

To isolate \(d\), we subtract 2 from each part of the inequality:
$$-5 - 2\leq d + 2 - 2\leq6 - 2$$
Simplifying each part, we get:
$$-7\leq d\leq4$$

Answer:

\(-7 \leq d \leq 4\) (So the first box is \(-7\) and the second box is \(4\))