Question

solve the following compound inequality. -3 ≤ 5 + 2x < 5

Explanation:

Step1: Subtract 5 from all parts

Subtract 5 from each part of the inequality $-3\leq5 + 2x<5$.
$-3-5\leq5 + 2x-5<5 - 5$
$-8\leq2x<0$

Step2: Divide by 2

Divide each part of the new - inequality $-8\leq2x<0$ by 2.
$\frac{-8}{2}\leq\frac{2x}{2}<\frac{0}{2}$
$-4\leq x<0$

Answer:

$-4\leq x<0$