QUESTION IMAGE
Question
solve the following problems according to the directions. show all work for full credit.
convert to moles
- $12.04 \times 10^{23}$ atoms he
- $3.01 \times 10^{23}$ atoms cu
- 100 atoms ar
- 1.0 atom s
- 24 grams c
- 59.3 grams sn
- 5000. grams k
- 0.00500 grams ne
convert to mass in grams
- 10.0 moles na
- 2.20 moles sn
- 5.00 moles ag
- $1.00 \times 10^{7}$ moles b
- $6.02 \times 10^{23}$ atoms ca
- $1.204 \times 10^{23}$ atoms bi
Convert to moles
Step1: Moles from atoms (Sn)
Use $\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}}$
$\text{Moles of Sn} = \frac{59.3\ \text{g}}{118.71\ \text{g/mol}}$
Step2: Calculate Sn moles
Compute the division
$\text{Moles of Sn} = 0.500\ \text{mol}$
Step3: Moles from mass (K)
Use $\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}}$
$\text{Moles of K} = \frac{5000.\ \text{g}}{39.10\ \text{g/mol}}$
Step4: Calculate K moles
Compute the division
$\text{Moles of K} = 128\ \text{mol}$
Step5: Moles from mass (Ne)
Use $\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}}$
$\text{Moles of Ne} = \frac{0.00500\ \text{g}}{20.18\ \text{g/mol}}$
Step6: Calculate Ne moles
Compute the division
$\text{Moles of Ne} = 2.48 \times 10^{-4}\ \text{mol}$
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Convert to mass in grams
Step7: Mass from moles (Na)
Use $\text{Mass} = \text{Moles} \times \text{Molar Mass}$
$\text{Mass of Na} = 10.0\ \text{mol} \times 22.99\ \text{g/mol}$
Step8: Calculate Na mass
Compute the multiplication
$\text{Mass of Na} = 230.\ \text{g}$
Step9: Mass from moles (Sn)
Use $\text{Mass} = \text{Moles} \times \text{Molar Mass}$
$\text{Mass of Sn} = 2.20\ \text{mol} \times 118.71\ \text{g/mol}$
Step10: Calculate Sn mass
Compute the multiplication
$\text{Mass of Sn} = 261\ \text{g}$
Step11: Mass from moles (Ag)
Use $\text{Mass} = \text{Moles} \times \text{Molar Mass}$
$\text{Mass of Ag} = 5.00\ \text{mol} \times 107.87\ \text{g/mol}$
Step12: Calculate Ag mass
Compute the multiplication
$\text{Mass of Ag} = 539\ \text{g}$
Step13: Mass from moles (B)
Use $\text{Mass} = \text{Moles} \times \text{Molar Mass}$
$\text{Mass of B} = 1.00 \times 10^7\ \text{mol} \times 10.81\ \text{g/mol}$
Step14: Calculate B mass
Compute the multiplication
$\text{Mass of B} = 1.08 \times 10^8\ \text{g}$
Step15: Mass from atoms (Ca)
First convert atoms to moles: $\text{Moles} = \frac{\text{Atoms}}{N_A}$, then $\text{Mass} = \text{Moles} \times \text{Molar Mass}$
$\text{Mass of Ca} = \frac{6.02 \times 10^{23}\ \text{atoms}}{6.02 \times 10^{23}\ \text{atoms/mol}} \times 40.08\ \text{g/mol}$
Step16: Calculate Ca mass
Simplify and compute
$\text{Mass of Ca} = 40.1\ \text{g}$
Step17: Mass from atoms (Bi)
First convert atoms to moles: $\text{Moles} = \frac{\text{Atoms}}{N_A}$, then $\text{Mass} = \text{Moles} \times \text{Molar Mass}$
$\text{Mass of Bi} = \frac{1.204 \times 10^{23}\ \text{atoms}}{6.02 \times 10^{23}\ \text{atoms/mol}} \times 208.98\ \text{g/mol}$
Step18: Calculate Bi mass
Simplify and compute
$\text{Mass of Bi} = 41.8\ \text{g}$
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Convert to moles
- $0.500\ \text{mol Sn}$
- $128\ \text{mol K}$
- $2.48 \times 10^{-4}\ \text{mol Ne}$
Convert to mass in grams
- $230.\ \text{g Na}$
- $261\ \text{g Sn}$
- $539\ \text{g Ag}$
- $1.08 \times 10^8\ \text{g B}$
- $40.1\ \text{g Ca}$
- $41.8\ \text{g Bi}$