Question

solve the following system of equations.
3x + 4y = 8
6x + 4y = 20
x =
y =

Explanation:

Step1: Subtract first equation from second

$(6x + 4y) - (3x + 4y) = 20 - 8$
Simplify: $3x = 12$

Step2: Solve for x

$x = \frac{12}{3} = 4$

Step3: Substitute x=4 into first equation

$3(4) + 4y = 8$
Simplify: $12 + 4y = 8$

Step4: Solve for y

$4y = 8 - 12 = -4$
$y = \frac{-4}{4} = -1$

Answer:

$x = 4$
$y = -1$