Question

solve the following system of equations. 6x + 3y = -6 2x - 3y = 14 x = y =

Explanation:

Step1: Add the two equations

$$(6x + 3y) + (2x - 3y) = -6 + 14$$
$$8x = 8$$

Step2: Solve for x

$$x = \frac{8}{8} = 1$$

Step3: Substitute x=1 into first equation

$$6(1) + 3y = -6$$
$$6 + 3y = -6$$

Step4: Isolate and solve for y

$$3y = -6 - 6 = -12$$
$$y = \frac{-12}{3} = -4$$

Answer:

$x = 1$
$y = -4$