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solve and graph the following inequality: -4 + 3x < -9x + 5

Question

solve and graph the following inequality: -4 + 3x < -9x + 5

Explanation:

Step1: Add 9x to both sides

$ - 4+3x + 9x<-9x + 9x+5$
$ - 4 + 12x<5$

Step2: Add 4 to both sides

$ - 4+4 + 12x<5 + 4$
$12x<9$

Step3: Divide both sides by 12

$x<\frac{9}{12}=\frac{3}{4}$

Answer:

$x<\frac{3}{4}$
To graph, on the number - line, draw an open circle at $\frac{3}{4}$ (because the inequality is strict, $x$ cannot equal $\frac{3}{4}$) and shade the line to the left of $\frac{3}{4}$.