Question

solve for r and graph the solution. 16 > 3r + 1. plot the endpoints. select an endpoint to change it from closed to open. select the middle of a segment, ray, or line to delete it.

Explanation:

Step1: Solve the inequality

Subtract 1 from both sides of $16>3r + 1$. We get $16-1>3r+1 - 1$, which simplifies to $15>3r$. Then divide both sides by 3: $\frac{15}{3}>\frac{3r}{3}$, so $5 > r$ or $r<5$.

Step2: Graph the solution

The solution $r < 5$ is an open - ended interval. On the number line, we use an open circle at 5 (because 5 is not included in the solution set, since the inequality is strict, $r<5$ not $r\leqslant5$) and draw a ray to the left to represent all the values of $r$ that satisfy the inequality.

Answer:

On the number line, place an open circle at 5 and draw a ray to the left.