Question

solve for j and graph the solution. 19 > j + 3 ≥ 3 plot the endpoints. select an endpoint to change it from closed to open. select the middle of a segment, ray, or line to delete it.

Explanation:

Step1: Solve left - hand side of inequality

Subtract 3 from all parts of $19>j + 3\geq3$. For the left - hand side $19>j + 3$, we get $19-3>j+3 - 3$, which simplifies to $16>j$.

Step2: Solve right - hand side of inequality

For the right - hand side $j + 3\geq3$, subtract 3 from both sides: $j+3 - 3\geq3 - 3$, which simplifies to $j\geq0$.

Answer:

$0\leq j<16$

To graph: Place a closed circle at 0 (because $j$ can equal 0) and an open circle at 16 (because $j$ cannot equal 16), and draw a line segment between them on the number line.