Question

solve for b and graph the solution.
0 < \frac{b + 18}{3} \leq 3
plot the endpoints. select an endpoint to change it from closed to open. select the middle of a segment, ray, or line to delete it.

Explanation:

Step1: Multiply each part by 3

Multiply all parts of the inequality $0 < \frac{b + 18}{3}\leq3$ by 3 to get $0\times3<\frac{b + 18}{3}\times3\leq3\times3$, which simplifies to $0 < b + 18\leq9$.

Step2: Subtract 18 from each part

Subtract 18 from all parts of the inequality $0 < b + 18\leq9$. We have $0-18 < b+18 - 18\leq9 - 18$, so $- 18 < b\leq - 9$.

Answer:

The solution for $b$ is $-18 < b\leq - 9$. On the number - line, there is an open circle at $-18$ and a closed circle at $-9$, and the line segment is drawn between them.