Question

solve the inequality
2(4x - 3) ≥ -3(3x) + 5x?
○ x ≥ 0.5
○ x ≥ 2
○ (-∞, 0.5
○ (-∞, 2

Explanation:

Step1: Expand both sides

$2(4x-3) = 8x - 6$; $-3(3x)+5x = -9x + 5x = -4x$
Inequality becomes: $8x - 6 \geq -4x$

Step2: Isolate x terms

Add $4x$ to both sides: $8x + 4x - 6 \geq 0$
$12x - 6 \geq 0$

Step3: Isolate the variable x

Add 6 to both sides: $12x \geq 6$
Divide by 12: $x \geq \frac{6}{12} = 0.5$

Answer:

$x \geq 0.5$