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Question
solve the inequality 4x < -8x + 12. write your answer as an inequality and in interval notation, then graph the solution set on the number line. for graphing: if the symbol in the inequality is < or >, use an open circle. if the symbol in the inequality is ≤ or ≥, use a closed circle. inequality: 4x < -8x + 12
Step1: Add \(8x\) to both sides
\[4x + 8x< - 8x+8x + 12\]
\[12x<12\]
Step2: Divide both sides by 12
\[\frac{12x}{12}<\frac{12}{12}\]
\[x < 1\]
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Inequality Notation: \(x<1\)
Graph: Use an open - circle at \(x = 1\) and draw an arrow to the left.
Interval Notation: \((-\infty,1)\)