Question

solve the inequality and graph the solution.
\\(\frac{j + 3}{-1}\leq1\\)
plot the endpoints. select an endpoint to change it from closed to open. select the middle of the segment, ray, or line to delete it.

Explanation:

Step1: Multiply both sides by -1

Multiply both sides of $\frac{j + 3}{-1}\leq1$ by - 1. Remember to reverse the inequality sign when multiplying by a negative number. So we get $j + 3\geq - 1$.

Step2: Subtract 3 from both sides

Subtract 3 from both sides of $j + 3\geq - 1$. We have $j\geq-1 - 3$, which simplifies to $j\geq - 4$.

Answer:

The solution of the inequality is $j\geq - 4$. On the number - line, we plot a closed circle at - 4 (because the inequality is $\geq$) and draw a ray to the right.