Question

i can solve multi-step mathematical problems.18. $5(b + 6) = 18$19. $\frac{1}{2}(6g + 2) = 12$20. $6m + 4(-2m + 6) = 10$21. $45 = -9(-p + 6)$22. $28 - 2(5a - 3) = 47$23. $17 + \frac{r}{3} = 28$

Explanation:

Step1: Solve 5(b+6)=18: Divide by 5

$\frac{5(b+6)}{5} = \frac{18}{5}$
$b+6 = 3.6$

Step2: Subtract 6 from both sides

$b = 3.6 - 6$
$b = -2.4$

Step3: Solve $\frac{1}{2}(6g+2)=12$: Multiply by 2

$2\times\frac{1}{2}(6g+2) = 2\times12$
$6g+2 = 24$

Step4: Subtract 2, divide by 6

$6g = 24-2=22$
$g = \frac{22}{6} = \frac{11}{3}$

Step5: Solve $6m+4(-2m+6)=10$: Expand terms

$6m -8m +24 = 10$
$-2m +24 = 10$

Step6: Subtract 24, divide by -2

$-2m = 10-24=-14$
$m = \frac{-14}{-2}=7$

Step7: Solve $45=-9(-p+6)$: Divide by -9

$\frac{45}{-9} = -p+6$
$-5 = -p+6$

Step8: Subtract 6, multiply by -1

$-5-6 = -p$
$-11 = -p$
$p=11$

Step9: Solve $28-2(5a-3)=47$: Expand terms

$28 -10a +6 = 47$
$34 -10a = 47$

Step10: Subtract 34, divide by -10

$-10a = 47-34=13$
$a = \frac{13}{-10}=-1.3$

Step11: Solve $17+\frac{r}{3}=28$: Subtract 17

$\frac{r}{3}=28-17=11$

Step12: Multiply by 3

$r=11\times3=33$

Answer:

1. $b = -2.4$
2. $g = \frac{11}{3}$
3. $m = 7$
4. $p = 11$
5. $a = -1.3$
6. $r = 33$