Question

solve.
paul has 547 beads. amy has 219 beads.
4 fill in the boxes.
547→ 500 + 40 + 7
+ 219→□+□+□

□+□+□
5 add hundreds, tens, and ones to solve.
show your work.
______ beads
a zoo has 146 birds and 628 bugs. it also
has 258 snakes and 338 fish.
6 how many birds and bugs are there?
show your work.
146
+ 628
answer: _____________
7 how many snakes and fish are there?
show your work.
258 + 338
answer: _____________

Explanation:

Question 4

Step1: Decompose 219

219 can be decomposed into hundreds, tens, and ones as \(200 + 10 + 9\).

Step2: Add corresponding place values

For the hundreds place: \(500+200 = 700\)
For the tens place: \(40 + 10=50\)
For the ones place: \(7+9 = 16\)

Step1: Decompose the numbers

Decompose 547 as \(500+40 + 7\) and 219 as \(200+10 + 9\).

Step2: Add hundreds, tens, ones separately

• Hundreds: \(500+200=700\)
• Tens: \(40 + 10 = 50\)
• Ones: \(7+9=16\)

Step3: Add the results of each place

Now add \(700+50 + 16\). First, \(700+50=750\), then \(750+16 = 766\).

Step1: Set up the addition

We need to add the number of birds (146) and bugs (628), so we calculate \(146+628\).

Step2: Add digit by digit (from right to left)

• Ones place: \(6 + 8=14\), write down 4 and carry over 1.
• Tens place: \(4+2 + 1=7\) (add the carried over 1)
• Hundreds place: \(1+6 = 7\)

Answer:

\(547\to500 + 40 + 7\)
\(+219\to\boldsymbol{200}+\boldsymbol{10}+\boldsymbol{9}\)
\(\overline{\quad\quad\quad\boldsymbol{700}+\boldsymbol{50}+\boldsymbol{16}}\)

Question 5