QUESTION IMAGE
Question
solve the right triangle.
image of right triangle with right angle at c, angle at b is 42.0897°, side ac = 50.851 cm, side bc labeled a, side ab labeled c
a = □° (round to four decimal places as needed.)
a = □ cm (round to three decimal places as needed.)
c = □ cm (round to three decimal places as needed.)
Step1: Find angle A
In a right triangle, the sum of the acute angles is \(90^\circ\). So \(A = 90^\circ - B\). Given \(B = 42.0897^\circ\), then \(A = 90 - 42.0897 = 47.9103^\circ\).
Step2: Find side a (opposite to angle B, adjacent to angle A)
We know that \(\tan B=\frac{AC}{a}\), where \(AC = 50.851\) cm. So \(a=\frac{AC}{\tan B}\). \(\tan(42.0897^\circ)\approx0.9063\), then \(a = \frac{50.851}{0.9063}\approx56.100\) cm.
Step3: Find side c (hypotenuse)
We know that \(\sin B=\frac{AC}{c}\), so \(c=\frac{AC}{\sin B}\). \(\sin(42.0897^\circ)\approx0.6708\), then \(c=\frac{50.851}{0.6708}\approx75.800\) cm.
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\(A = 47.9103^\circ\)
\(a = 56.100\) cm
\(c = 75.800\) cm