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Question
solve.
\\(\sqrt3{7x - 1} - 3 = 0\\)
select the correct choice below and fill in any answer boxes present in your choice.
a. \\(x = \\) (simplify your answer. use a comma to separate answers as needed.)
b. there is no solution.
Step1: Isolate the cube root
$\sqrt[3]{7x-1} = 3$
Step2: Cube both sides
$(\sqrt[3]{7x-1})^3 = 3^3$
$7x - 1 = 27$
Step3: Solve for x
$7x = 27 + 1$
$7x = 28$
$x = \frac{28}{7}$
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