Question

solve the system of equations.
$-3y - 4x = -11$
$3y - 5x = -61$
$x = square$
$y = square$

Explanation:

Step1: Add the two equations

$$(-3y - 4x) + (3y - 5x) = -11 + (-61)$$
Simplify: $-9x = -72$

Step2: Solve for $x$

$$x = \frac{-72}{-9} = 8$$

Step3: Substitute $x=8$ into second equation

$$3y - 5(8) = -61$$
Simplify: $3y - 40 = -61$

Step4: Solve for $y$

$$3y = -61 + 40 = -21$$
$$y = \frac{-21}{3} = -7$$

Answer:

$x = 8$
$y = -7$