Question

solve the system of linear equations by substitution.
$6x - 9 = y$
$y = -3x$
$\left(\square, \square\
ight)$

Explanation:

Step1: Substitute $y=-3x$ into first equation

$6x - 9 = -3x$

Step2: Isolate $x$ terms

$6x + 3x = 9$
$9x = 9$

Step3: Solve for $x$

$x = \frac{9}{9} = 1$

Step4: Substitute $x=1$ into $y=-3x$

$y = -3\times1 = -3$

Answer:

$(1, -3)$