QUESTION IMAGE
Question
solve the system by the method of your choice.\
\select the correct choice below and, if necessary, fill in the answer box to complete your choice.\\(\bigcirc\\) a. there is exactly one solution. the solution set is \\(\\{\quad\\}\\).\\(\quad\\) (simplify your answer. type an ordered pair.)\\(\bigcirc\\) b. there are infinitely many solutions. the solution set is \\(\\{(x,y)|6(x - 6) - 5y = 0\\}\\) or \\(\\{(x,y)|5(x - y) = -x - 6\\}\\).\\(\bigcirc\\) c. the solution set is \\(\varnothing\\).
Step1: Simplify the first equation
Start with \( 6(x - 6) - 5y = 0 \).
Expand the left - hand side: \( 6x-36 - 5y=0 \).
Rearrange it to the standard form \( 6x-5y=36 \). Let's call this Equation (1).
Step2: Simplify the second equation
Start with \( 5(x - y)=-x - 6 \).
Expand the left - hand side: \( 5x-5y=-x - 6 \).
Add \( x \) to both sides: \( 5x + x-5y=-6 \).
Combine like terms: \( 6x-5y=-6 \). Let's call this Equation (2).
Step3: Analyze the two equations
We have Equation (1): \( 6x - 5y=36 \) and Equation (2): \( 6x - 5y=-6 \).
Let \( A = 6x-5y \). Then Equation (1) says \( A = 36 \) and Equation (2) says \( A=-6 \). But a single expression \( A \) cannot be equal to two different values at the same time. This means that the system of equations has no solution.
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C. The solution set is \(\varnothing\).