Question

solve the system by substitution. 8x + 7y = -47 4y - 1 = x answer attempt 1 out of 2 (□,□) submit answer

Explanation:

Step1: Substitute \( x = 4y - 1 \) into the first equation

We have the first equation \( 8x + 7y = -47 \) and \( x = 4y - 1 \). Substitute \( x \) in the first equation:
\( 8(4y - 1) + 7y = -47 \)

Step2: Simplify and solve for \( y \)

Expand the left - hand side: \( 32y-8 + 7y=-47 \)
Combine like terms: \( 32y+7y=-47 + 8 \)
\( 39y=-39 \)
Divide both sides by 39: \( y=\frac{-39}{39}=-1 \)

Step3: Substitute \( y = - 1 \) into \( x = 4y - 1 \) to find \( x \)

\( x=4\times(-1)-1=-4 - 1=-5 \)

Answer:

\((-5,-1)\)