Question

solve the system by substitution.
$-x - 3 = y$
$-3x - 8y = 4$
answer attempt 1 out of 3
$(square, square)$ submit answer

Explanation:

Step1: Substitute \( y = -x - 3 \) into the second equation

The second equation is \( -3x - 8y = 4 \). Substitute \( y \) with \( -x - 3 \):
\[
-3x - 8(-x - 3) = 4
\]

Step2: Simplify and solve for \( x \)

First, distribute the -8:
\[
-3x + 8x + 24 = 4
\]
Combine like terms:
\[
5x + 24 = 4
\]
Subtract 24 from both sides:
\[
5x = 4 - 24
\]
\[
5x = -20
\]
Divide both sides by 5:
\[
x = \frac{-20}{5} = -4
\]

Step3: Substitute \( x = -4 \) back into \( y = -x - 3 \) to find \( y \)

\[
y = -(-4) - 3
\]
\[
y = 4 - 3 = 1
\]

Answer:

\((-4, 1)\)