Question

solve $6.13 \div 5$ using the division algorithm. divide 6 ones by 5. then multiply to show how many ones you shared. finally, subtract to show many ones you have left. \\\

$$\begin{array}{r} \\boxed{1}. \\\\ 5 \\overline{)6.13} \\\\ -\\boxed{} \\\\ \\boxed{} \\\\ \\end{array}$$

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Explanation:

Step1: Multiply quotient digit (1) by divisor (5)

We know that the quotient digit in the ones place is 1. To find the number to subtract, we multiply the quotient digit (1) by the divisor (5). So, \(1\times5 = 5\).

Step2: Subtract to find the remainder in ones place

We start with 6 ones (from the dividend 6.13, the whole number part is 6 which is 6 ones). We subtract the product we found (5) from 6. So, \(6 - 5=1\).

Answer:

The first box (the product) is \(5\) and the second box (the remainder) is \(1\). So filling in the boxes, we have \(-\boxed{5}\) and then \(\boxed{1}\) below it.