Question

5.3 solving by elimination practice
question
find the solution of the system of equations.
$2x + 8y = 4$
$6x - y = -13$
answer attempt 1 out of 2
( , ) submit answer

Explanation:

Step1: Scale second equation

Multiply the second equation by 8 to align y terms.
$$8\times(6x - y) = 8\times(-13) \implies 48x - 8y = -104$$

Step2: Add equations to eliminate y

Add the scaled equation to the first equation.
$$(2x + 8y) + (48x - 8y) = 4 + (-104)$$
$$50x = -100$$

Step3: Solve for x

Divide both sides by 50 to isolate x.
$$x = \frac{-100}{50} = -2$$

Step4: Substitute x to find y

Plug $x=-2$ into $6x - y = -13$.
$$6(-2) - y = -13 \implies -12 - y = -13$$
$$-y = -13 + 12 \implies -y = -1 \implies y = 1$$

Answer:

$(-2, 1)$