Question

solving a quadratic equation when a ≠ 1 by completing the square
consider (8x^2 - 48x = -104).
write the equation so that
a = 1, (x^2 + square x = square) (with filled values 6 and -13)
complete the square
(x^2 - 6x + square = -13 + square)

Explanation:

Step1: Identify coefficient of x

For $x^2 - 6x$, coefficient is $-6$.

Step2: Compute half the coefficient

$\frac{-6}{2} = -3$

Step3: Square the result

$(-3)^2 = 9$

Step4: Balance both sides

Add 9 to each side of the equation.

Answer:

$x^2 - 6x + \boldsymbol{9} = -13 + \boldsymbol{9}$