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solving quadratic equations using common factors quick check which of t…

Question

solving quadratic equations using common factors quick check
which of the following quadratic equations can be solved by grouping? (1 point)
\\( x^2 - 4x - 8 = 0 \\)
\\( x^2 - 12x + 18 = 0 \\)
\\( x^2 + 8x - 22 = 0 \\)
\\( x^2 + 10x + 21 = 0 \\)

Explanation:

To determine which quadratic equation can be solved by grouping, we need to check if the equation can be factored into two binomials. For a quadratic equation \(ax^2 + bx + c = 0\) (where \(a = 1\) in all these cases), we need two numbers that multiply to \(c\) and add up to \(b\).

Step 1: Analyze \(x^2 - 4x - 8 = 0\)

We need two numbers that multiply to \(-8\) and add to \(-4\). The factors of \(-8\) are: \(\pm1, \pm2, \pm4, \pm8\). Let's check the pairs:

  • \(1\) and \(-8\): \(1 + (-8) = -7\)
  • \(2\) and \(-4\): \(2 + (-4) = -2\)

None of these pairs add up to \(-4\), so this equation cannot be solved by grouping.

Step 2: Analyze \(x^2 - 12x + 18 = 0\)

We need two numbers that multiply to \(18\) and add to \(-12\). The factors of \(18\) are: \(1, 2, 3, 6, 9, 18\). Since the product is positive and the sum is negative, both numbers should be negative.

  • \(-1\) and \(-18\): \(-1 + (-18) = -19\)
  • \(-2\) and \(-9\): \(-2 + (-9) = -11\)
  • \(-3\) and \(-6\): \(-3 + (-6) = -9\)

None of these pairs add up to \(-12\), so this equation cannot be solved by grouping.

Step 3: Analyze \(x^2 + 8x - 22 = 0\)

We need two numbers that multiply to \(-22\) and add to \(8\). The factors of \(-22\) are: \(\pm1, \pm2, \pm11, \pm22\). Let's check the pairs:

  • \(11\) and \(-2\): \(11 + (-2) = 9\)
  • \(22\) and \(-1\): \(22 + (-1) = 21\)

None of these pairs add up to \(8\), so this equation cannot be solved by grouping.

Step 4: Analyze \(x^2 + 10x + 21 = 0\)

We need two numbers that multiply to \(21\) and add to \(10\). The factors of \(21\) are: \(1, 3, 7, 21\).

  • \(3\) and \(7\): \(3 \times 7 = 21\) and \(3 + 7 = 10\)

So, we can factor the equation as \((x + 3)(x + 7) = 0\), which means it can be solved by grouping.

Answer:

\(x^2 + 10x + 21 = 0\) (the last option, i.e., the option with the equation \(x^2 + 10x + 21 = 0\))