Question

solving quadratics with square roots (level 1)
score: 2/5 penalty: 1 off
question
solve the following quadratic equation for all values of x in simplest form.
2(x² - 6) - 1 = -5
answer attempt 1 out of 2
autosaved solution no solution
x =
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Explanation:

Step1: Simplify left side constants

$2(x^2 - 6) - 1 = -5$
$2x^2 - 12 - 1 = -5$
$2x^2 - 13 = -5$

Step2: Isolate the $x^2$ term

$2x^2 = -5 + 13$
$2x^2 = 8$

Step3: Solve for $x^2$

$x^2 = \frac{8}{2}$
$x^2 = 4$

Step4: Take square root of both sides

$x = \pm\sqrt{4}$
$x = \pm2$

Answer:

$x = 2$ and $x = -2$