QUESTION IMAGE
Question
solving right triangles
date: 2/9/2
find the missing side. round to the nearest tenth.
1)
2)
3)
4)
5)
6)
7)
8)
Step1: Use tangent for angle 72°
$\tan(72^\circ) = \frac{x}{6}$
$x = 6 \times \tan(72^\circ) \approx 6 \times 3.078 = 18.5$
Step2: Use tangent for angle 79°
$\tan(79^\circ) = \frac{8}{x}$
$x = \frac{8}{\tan(79^\circ)} \approx \frac{8}{5.145} = 1.6$
Step3: Use tangent for angle 24°
$\tan(24^\circ) = \frac{x}{12}$
$x = 12 \times \tan(24^\circ) \approx 12 \times 0.445 = 5.3$
Step4: Use tangent for angle 37°
$\tan(37^\circ) = \frac{x}{12}$
$x = 12 \times \tan(37^\circ) \approx 12 \times 0.754 = 9.0$
Step5: Use tangent for angle 40°
$\tan(40^\circ) = \frac{14}{x}$
$x = \frac{14}{\tan(40^\circ)} \approx \frac{14}{0.839} = 16.7$
Step6: Use tangent for angle 51°
$\tan(51^\circ) = \frac{x}{14}$
$x = 14 \times \tan(51^\circ) \approx 14 \times 1.235 = 17.3$
Step7: Use tangent for angle 60°
$\tan(60^\circ) = \frac{x}{16}$
$x = 16 \times \tan(60^\circ) \approx 16 \times 1.732 = 27.7$
Step8: Use tangent for angle 15°
$\tan(15^\circ) = \frac{10}{x}$
$x = \frac{10}{\tan(15^\circ)} \approx \frac{10}{0.268} = 37.3$
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- $18.5$
- $1.6$
- $5.3$
- $9.0$
- $16.7$
- $17.3$
- $27.7$
- $37.3$