Question

a space agency launched two rockets. the first rocket reached a height of $5 \times 10^3$ feet (ft) and the second one reached a height of $10 \times 10^4$ ft. approximately how much higher did the second rocket fly compared to the first rocket?\
$2 \times 10^1$ ft\
$1 \times 10^5$ ft\
$1 \times 10^7$ ft\
$2 \times 10^5$ ft

Explanation:

Step1: Divide the two heights

$\frac{10 \times 10^4}{5 \times 10^3}$

Step2: Simplify the coefficients

$\frac{10}{5} = 2$

Step3: Simplify the powers of 10

$\frac{10^4}{10^3} = 10^{4-3} = 10^1$

Step4: Multiply the results

$2 \times 10^1$

Answer:

A. $2 \times 10^1$ ft