Question

1. \\(sqrt{12}(sqrt{3} + sqrt{6})\\)

Explanation:

Step1: Distribute $\sqrt{12}$ to terms inside

$\sqrt{12} \times \sqrt{3} + \sqrt{12} \times \sqrt{6}$

Step2: Simplify each product using $\sqrt{a}\sqrt{b}=\sqrt{ab}$

$\sqrt{12 \times 3} + \sqrt{12 \times 6}$

Step3: Calculate products inside radicals

$\sqrt{36} + \sqrt{72}$

Step4: Simplify the square roots

$6 + 6\sqrt{2}$

Answer:

$6 + 6\sqrt{2}$