Question

square roots and the pythagorean theorem
vectored instruction
find the length of “c” to the nearest tenth using the pythagorean theorem.

Explanation:

Step1: Recall Pythagorean Theorem

$a^{2}+b^{2}=c^{2}$, where $a = 7$, $b = 8$

Step2: Substitute values

$7^{2}+8^{2}=c^{2}$, so $49 + 64=c^{2}$, then $c^{2}=113$

Step3: Solve for c

$c=\sqrt{113}\approx 10.6$

Answer:

$10.6$