Question

sra 18 - standard (15261)
tial decay functions
which is the graph of $f(x) = 100(0.7)^x$

Explanation:

Step1: Find y-intercept (x=0)

Substitute $x=0$ into $f(x)=100(0.7)^x$:
$f(0)=100(0.7)^0=100(1)=100$
All graphs have the point $(0,100)$, so check another point.

Step2: Calculate f(2)

Substitute $x=2$ into the function:
$f(2)=100(0.7)^2=100(0.49)=49$
This means the graph must pass through the point $(2,49)$.

Answer:

The rightmost graph (with points (0,100) and (2,49))