Question

staar-formatted practice - probability review charles has two number cubes. the faces of each number cube are numbered from 1 to 6. charles will roll each number cube one time. move the correct answer to each box to show the probability of rolling a 5 on the first number cube and an even number on the second number cube. not all answers will be used. 1 1 × = boxes

Explanation:

Step1: Probability of rolling a 5 on first cube

A number cube has 6 faces (1 - 6). The number of favorable outcomes (rolling a 5) is 1. So the probability is $\frac{1}{6}$.

Step2: Probability of rolling an even number on second cube

Even numbers on a cube (1 - 6) are 2, 4, 6. So there are 3 favorable outcomes. The probability is $\frac{3}{6}=\frac{1}{2}$.

Step3: Multiply the two probabilities

To find the probability of both events happening, we multiply the probabilities of each event. So $\frac{1}{6} \times \frac{1}{2} = \frac{1}{12}$.

Answer:

$\frac{1}{6} \times \frac{1}{2} = \frac{1}{12}$ (So the first blank is $\frac{1}{6}$, the second blank is $\frac{1}{2}$, and the result is $\frac{1}{12}$)