Question

1. the standard equation of a circle is $(x - h)^2+(y - k)^2=r^2$. rearrange the equation for $h$.

$h=sqrt{r^{2}-(y - k)^{2}}-x$
$h=sqrt{r^{2}-(y - k)^{2}}-x$
$h=r^{2}-(y - k)^{2}-x$
$h=-sqrt{r^{2}-(y - k)^{2}}+x$

Explanation:

Step1: Isolate $(x - h)^2$

$(x - h)^2=r^2-(y - k)^2$

Step2: Take square - root of both sides

$x - h=\pm\sqrt{r^2-(y - k)^2}$

Step3: Solve for h

$h=x\mp\sqrt{r^2-(y - k)^2}$

Answer:

$h = x-\sqrt{r^{2}-(y - k)^{2}}$ or $h=x+\sqrt{r^{2}-(y - k)^{2}}$ (None of the given options are correct)