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step 6: calculate the prec y of the falling soda bottles in this part o…

Question

step 6: calculate the prec y of the falling soda bottles
in this part of the experiment, you will be cha speed of the bottle by dropping it from differe you will use the same mass, 0.250 kg, for ea record this mass in table b for each velocity. calculate the expected kinetic energy (ke) at velocity. use the formula ( ke = \frac{1}{2}mv^2 ),
where ( m ) is the mass and ( v ) is the speed. rec calculations in table b of your student guide.
the bottle is 2 m/s, the ke is
the bottle is 3 m/s, the ke is
the bottle is 4 m/s, the ke is
when the speed of the bottle is 5 m/s, the ke is ( \boxed{} ) kg • m²/s².

Explanation:

Step1: Identify given values

Mass \( m = 0.250 \, \text{kg} \), velocity \( v = 5 \, \text{m/s} \), kinetic energy formula \( KE=\frac{1}{2}mv^{2} \)

Step2: Substitute values into formula

Substitute \( m = 0.250 \) and \( v = 5 \) into \( KE=\frac{1}{2}mv^{2} \)
\( KE=\frac{1}{2}\times0.250\times(5)^{2} \)

Step3: Calculate the result

First, calculate \( (5)^{2}=25 \)
Then, \( \frac{1}{2}\times0.250\times25 = 0.125\times25 = 3.125 \)

Answer:

\( 3.125 \)