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Question
the stick game, played by various native american tribes, involves dropping flat sticks painted on one side and unpainted on the other side. points are awarded based on the combination of painted and unpainted sides that land face up.
this table shows the frequency of the points awarded to players in 50 turns during one game.
| point value | 2 | 3 | 5 | 10 |
| number of times awarded | 21 | 18 | 6 | 5 |
points awarded to players
based on these data, which table shows the probability of awarding each possible point value to a player on a turn?
| outcome | 2 | 3 | 5 | 10 |
| probability | 11/100 | 18/100 | 6/100 | 5/100 |
| outcome | 2 | 3 | 5 | 10 |
| probability | 2/20 | 3/20 | 5/20 | 10/20 |
| outcome | 2 | 3 | 5 | 10 |
| probability | 21/50 | 18/50 | 6/50 | 5/50 |
| outcome | 2 | 3 | 5 | 10 |
| probability | 1/4 | 1/4 | 1/4 | 1/4 |
Step1: Recall probability formula
The probability $P$ of an event is given by $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. The total number of turns is $n = 21+18 + 6+5=50$.
Step2: Calculate probability for point - value 2
For a point - value of 2, the number of times it was awarded is 21. So the probability $P(2)=\frac{21}{50}$.
Step3: Calculate probability for point - value 3
For a point - value of 3, the number of times it was awarded is 18. So the probability $P(3)=\frac{18}{50}$.
Step4: Calculate probability for point - value 5
For a point - value of 5, the number of times it was awarded is 6. So the probability $P(5)=\frac{6}{50}$.
Step5: Calculate probability for point - value 10
For a point - value of 10, the number of times it was awarded is 5. So the probability $P(10)=\frac{5}{50}$.
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The table with probabilities $\frac{21}{50},\frac{18}{50},\frac{6}{50},\frac{5}{50}$ for point - values 2, 3, 5, 10 respectively.