Question

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table.
bedroom areas

area (sq. ft)	number of bedrooms
$80\leq a<100$	6
$100\leq a<120$	5
$120\leq a<140$	3
$140\leq a<160$	1

create a histogram to represent the data. which statement is most likely true about the mean and the median of the data?
○ the histogram is right-skewed, so the mean is less than the median.
○ the histogram is right-skewed, so the mean is greater than the median.
○ the histogram is left-skewed, so the mean is less than the median.
○ the histogram is left-skewed, so the mean is greater than the median.

Explanation:

Step1: Identify data distribution

First, observe the frequency table: the highest frequencies are in the smaller area intervals (60-80, 80-100), and frequencies decrease as area increases. This means the histogram will have a tail extending to the right (higher values), so it is right-skewed.

Step2: Relate skew to mean/median

In a right-skewed distribution, the mean is pulled toward the long tail (higher values), making it greater than the median.

Answer:

The histogram is right-skewed, so the mean is greater than the median.