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the students in marlys math class recorded the dimensions of their bedr…

Question

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas

area (sq. ft)number of bedrooms
80 ≤ a < 1006
100 ≤ a < 1205
120 ≤ a < 1403
140 ≤ a < 1601

create a histogram to represent the data. which statement is most likely true about the mean and the median of the data?
the histogram is right - skewed, so the mean is less than the median.
the histogram is right - skewed, so the mean is greater than the median.
the histogram is left - skewed, so the mean is less than the median.
the histogram is left - skewed, so the mean is greater than the median.

Explanation:

Step1: Analizar la frecuencia

Observamos que la frecuencia disminuye a medida que el área aumenta.

Step2: Identificar la asimetría

Con la frecuencia decreciente para valores más altos, la distribución es right - skewed.

Step3: Comprender la relación media - mediana

En una distribución right - skewed, los valores extremos en la cola derecha elevan la media, por lo que la media es mayor que la mediana.

Answer:

The histogram is right - skewed, so the mean is greater than the median.