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sub work 2.11.26 solving two step equations 1) $3y + 6 = 12$ 2) $10 + 3…

Question

sub work 2.11.26
solving two step equations

  1. $3y + 6 = 12$
  2. $10 + 3v = 25$
  3. $2x + 8 = 16$

Explanation:

1) Step1: Isolate the term with $y$

Subtract 6 from both sides:
$3y + 6 - 6 = 12 - 6$
$3y = 6$

1) Step2: Solve for $y$

Divide both sides by 3:
$\frac{3y}{3} = \frac{6}{3}$
$y = 2$

2) Step1: Isolate the term with $v$

Subtract 10 from both sides:
$10 + 3v - 10 = 25 - 10$
$3v = 15$

2) Step2: Solve for $v$

Divide both sides by 3:
$\frac{3v}{3} = \frac{15}{3}$
$v = 5$

3) Step1: Isolate the term with $x$

Subtract 8 from both sides:
$2x + 8 - 8 = 16 - 8$
$2x = 8$

3) Step2: Solve for $x$

Divide both sides by 2:
$\frac{2x}{2} = \frac{8}{2}$
$x = 4$

Answer:

  1. $y=2$
  2. $v=5$
  3. $x=4$