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if $angle z$ and $angle x$ are supplementary and $mangle z = 41^{circ}$…

Question

if $angle z$ and $angle x$ are supplementary and $mangle z = 41^{circ}$, solve for $mangle x$.

Explanation:

Step1: Recall supplementary - angle definition

Supplementary angles add up to 180°. So, $m\angle x + m\angle z=180^{\circ}$.

Step2: Substitute the value of $m\angle z$

Given $m\angle z = 41^{\circ}$, we have $m\angle x+41^{\circ}=180^{\circ}$.

Step3: Solve for $m\angle x$

$m\angle x=180^{\circ}- 41^{\circ}=139^{\circ}$.

Answer:

$m\angle x = 139^{\circ}$