Question

suppose triangle abc will be dilated using the rule $d_{q,\frac{2}{3}}$. what will be the distance from the center of dilation, q, to the image of vertex a? 2 units 3 units 4 units 6 units

Explanation:

Step1: Identify the original distance

The original distance from the center of dilation \( Q \) to vertex \( A \) is given as \( 6 \) units.

Step2: Apply the dilation rule

The dilation rule is \( D_{Q,\frac{2}{3}} \), which means we multiply the original distance by the scale factor \( \frac{2}{3} \). So we calculate \( 6\times\frac{2}{3} \).

Step3: Perform the calculation

\( 6\times\frac{2}{3}=\frac{12}{3} = 4 \) units.

Answer:

4 units (corresponding to the option "4 units")