Question

suppose you spin the spinner below 5 times. which probabilities do you need in order to calculate p(getting a on 2 or fewer spins)? p(0 successes) p(1 success) p(2 successes) p(3 successes) p(4 successes) p(5 successes) complete p(getting a on 2 or fewer spins) = done 0.21 0.329 0.658 none

Explanation:

Step1: Recall probability - addition rule

The probability of getting A on 2 or fewer spins is the sum of the probabilities of getting 0, 1, and 2 successes.

Step2: Write the formula

$P(\text{getting A on 2 or fewer spins})=P(0\text{ successes}) + P(1\text{ success})+P(2\text{ successes})$

Answer:

$P(0\text{ successes}) + P(1\text{ success})+P(2\text{ successes})$