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a survey was given to a random sample of the residents of a town to det…

Question

a survey was given to a random sample of the residents of a town to determine whether they support a new plan to raise taxes in order to increase education spending. the survey reported a confidence interval that between 75% and 83% of the residents supports the plan. what is the margin of error on the survey? do not write ± on the margin of error.

Explanation:

Step1: Encontrar la diferencia entre los límites del intervalo de confianza

La fórmula para el margen de error en un intervalo de confianza para una proporción es la mitad de la diferencia entre los límites superiores e inferiores. Los límites son $p_1 = 0.75$ y $p_2=0.83$.
$Diferencia=p_2 - p_1$
$Diferencia = 0.83 - 0.75=0.08$

Step2: Calcular el margen de error

El margen de error $E$ es la mitad de la diferencia calculada anteriormente.
$E=\frac{Diferencia}{2}$
$E=\frac{0.08}{2}=0.04$

Answer:

0.04