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svlc algebra 1a - standard (15260) solving linear equations: variable o…

Question

svlc algebra 1a - standard (15260)
solving linear equations: variable on one side
solve the equation.
$5x + 8 - 3x = -10$
$x = 9$
$x = -9$
$x = 1$
$x = -1$

Explanation:

Step1: Combine like terms

First, combine the \(x\)-terms on the left side of the equation. We have \(5x - 3x\), which simplifies to \(2x\). So the equation becomes:
\(2x + 8 = -10\)

Step2: Subtract 8 from both sides

To isolate the term with \(x\), we subtract 8 from both sides of the equation:
\(2x + 8 - 8 = -10 - 8\)
\(2x = -18\)

Step3: Divide by 2

Now, divide both sides of the equation by 2 to solve for \(x\):
\(\frac{2x}{2} = \frac{-18}{2}\)
\(x = -9\)

Answer:

\(x = -9\) (corresponding to the option: \(x = -9\))