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Question
systems of equations graphing method
graded assignment (show all work!!!) name:
date: period :
use graphing method to solve and name the type of solutions
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Problem 1
Step1: Analyze the first equation
The first equation is \( x = -4 \), which is a vertical line passing through \( x = -4 \) on the x - axis.
Step2: Substitute \( x=-4 \) into the second equation
The second equation is \( 3x + 4y=8 \). Substitute \( x = - 4\) into it:
\[
\]
Step3: Graph the lines
The line \( x=-4 \) is vertical. The line \( 3x + 4y = 8\) can be rewritten in slope - intercept form (\(y=mx + b\)) as \(y=-\frac{3}{4}x + 2\) (by solving \(3x + 4y=8\) for \(y\): \(4y=-3x + 8\), \(y =-\frac{3}{4}x+2\)). The two lines intersect at the point \((-4,5)\). Since the two lines intersect at exactly one point, the system has one unique solution.
Step1: Analyze the equations
The system is \(
\). Let's rewrite the second equation in slope - intercept form. Solve \(6x-3y=-3\) for \(y\):
\[
\]
Step2: Compare the slopes and y - intercepts
The first equation \(y = 2x-4\) has a slope \(m_1 = 2\) and y - intercept \(b_1=-4\). The second equation \(y = 2x + 1\) has a slope \(m_2=2\) and y - intercept \(b_2 = 1\). Since the slopes are equal (\(m_1=m_2\)) and the y - intercepts are different (\(b_1
eq b_2\)), the two lines are parallel. Parallel lines never intersect, so the system has no solution.
Step1: Analyze the equations
The system is \(
\). Both equations are the same. This means that the two lines are coincident (they lie on top of each other).
Step2: Determine the number of solutions
When two lines are coincident, they intersect at infinitely many points. So the system has infinitely many solutions.
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\((-4,5)\) (one unique solution)